富贵资源网 Design By www.hznty.com
以下有两个表,他们的结构完全相同,请通过SQL找出值不同的列。
Student_1
NAME AGE SCORE peter 26 100 jack 25 96 daniel 26 48 bark 21 69
Student_2
NAME AGE SCORE peter 26 89 jack 25 96 daniel 26 48 bark 21 69
方法一 -- NOT EXISTS:
复制代码 代码如下:
SELECT *
FROM Student_1 S1
WHERE NOT EXISTS
(SELECT *
FROM Student_2 S2
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
)
UNION ALL
SELECT *
FROM STUDENT_2 S2
WHERE NOT EXISTS
(SELECT *
FROM STUDENT_1 S1
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
);
方法二 -- MINUS
复制代码 代码如下:
(SELECT * FROM Student_1
MINUS
SELECT * FROM Student_2)
UNION ALL
(SELECT * FROM Student_2
MINUS
SELECT * FROM Student_1)
方法三 -- HAVING GROUP BY
复制代码 代码如下:
SELECT DISTINCT name, age, score FROM (
SELECT * FROM Student_1
UNION ALL
SELECT * FROM Student_2
)GROUP BY name, age, score HAVING COUNT(*)=1 ;
富贵资源网 Design By www.hznty.com
广告合作:本站广告合作请联系QQ:858582 申请时备注:广告合作(否则不回)
免责声明:本站资源来自互联网收集,仅供用于学习和交流,请遵循相关法律法规,本站一切资源不代表本站立场,如有侵权、后门、不妥请联系本站删除!
免责声明:本站资源来自互联网收集,仅供用于学习和交流,请遵循相关法律法规,本站一切资源不代表本站立场,如有侵权、后门、不妥请联系本站删除!
富贵资源网 Design By www.hznty.com
暂无评论...